4(5x+1)=12(20x+16)+16

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Solution for 4(5x+1)=12(20x+16)+16 equation: 



4(5x+1)=12(20x+16)+16

We move all terms to the left:

4(5x+1)-(12(20x+16)+16)=0

We multiply parentheses

20x-(12(20x+16)+16)+4=0



We calculate terms in parentheses: -(12(20x+16)+16), so:

12(20x+16)+16

We multiply parentheses

240x+192+16

We add all the numbers together, and all the variables

240x+208

Back to the equation:

-(240x+208)



We get rid of parentheses

20x-240x-208+4=0

We add all the numbers together, and all the variables

-220x-204=0

We move all terms containing x to the left, all other terms to the right

-220x=204

x=204/-220

x=-51/55

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