4(5x+1)=25+3(2x-1)

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Solution for 4(5x+1)=25+3(2x-1) equation: 



4(5x+1)=25+3(2x-1)

We move all terms to the left:

4(5x+1)-(25+3(2x-1))=0

We multiply parentheses

20x-(25+3(2x-1))+4=0



We calculate terms in parentheses: -(25+3(2x-1)), so:

25+3(2x-1)

determiningTheFunctionDomain
3(2x-1)+25

We multiply parentheses

6x-3+25

We add all the numbers together, and all the variables

6x+22

Back to the equation:

-(6x+22)



We get rid of parentheses

20x-6x-22+4=0

We add all the numbers together, and all the variables

14x-18=0

We move all terms containing x to the left, all other terms to the right

14x=18

x=18/14

x=1+2/7

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