If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4(5x+12)=2(10x+24)
We move all terms to the left:
4(5x+12)-(2(10x+24))=0
We multiply parentheses
20x-(2(10x+24))+48=0
We calculate terms in parentheses: -(2(10x+24)), so:We get rid of parentheses
2(10x+24)
We multiply parentheses
20x+48
Back to the equation:
-(20x+48)
20x-20x-48+48=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
| x5=x6 | | 12x-35=25 | | 5-8(x-1)=3 | | 5(j-4)=j=-8 | | 2/3x-3=1/2x+7 | | 6x-9+6=2x-10-6x | | 2÷b+4=9 | | 5-4(-2x-8)=5 | | -2/n=4/8 | | 157=-7(4v-7)-8v | | 10x÷5=16 | | 5-4-2x-8=5 | | (2x+8)^2=25 | | n/2=3/6 | | 2(3-x)+3x=12 | | 2(x+12)=-10 | | -1(4x+8)=-16 | | X^2+2x=234 | | 10/9(t-1)=-7/3(-2t-3)-1/18 | | -3x-6x-4=9 | | 4x+2(-3)=14 | | -6+m=-10 | | 6(4u-1)-2(6u-4)=13 | | 24+8x=20 | | 4/5=8/4(x+4) | | (2x+4+4x)=0 | | 7p-(3p+4)=-2(20-1)=10 | | 4x-(3x+9)=7x-27 | | -17.2x+5.3x+(-9.3)=10.2 | | 3w^2+6w-4=9-2w | | (20x^2-29x+5)(x-2)=0 | | -6u+3+7=4u-2 |