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4(5x+3)=2(6x-4)
We move all terms to the left:
4(5x+3)-(2(6x-4))=0
We multiply parentheses
20x-(2(6x-4))+12=0
We calculate terms in parentheses: -(2(6x-4)), so:We get rid of parentheses
2(6x-4)
We multiply parentheses
12x-8
Back to the equation:
-(12x-8)
20x-12x+8+12=0
We add all the numbers together, and all the variables
8x+20=0
We move all terms containing x to the left, all other terms to the right
8x=-20
x=-20/8
x=-2+1/2
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