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((4*(5*x-1))/3)*(x-6) = 0
(4*(5*x-1)*(x-6))/3 = 0
( 4 )
4 = 0
x belongs to the empty set
( 5*x-1 )
5*x-1 = 0 // + 1
5*x = 1 // : 5
x = 1/5
( x-6 )
x-6 = 0 // + 6
x = 6
x in { 1/5, 6 }
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