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4(5x-15)=5(x-3)
We move all terms to the left:
4(5x-15)-(5(x-3))=0
We multiply parentheses
20x-(5(x-3))-60=0
We calculate terms in parentheses: -(5(x-3)), so:We get rid of parentheses
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
20x-5x+15-60=0
We add all the numbers together, and all the variables
15x-45=0
We move all terms containing x to the left, all other terms to the right
15x=45
x=45/15
x=3
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