4(5x-2)/4-6(3x+2)/7=42-5(7x-4)/4

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Solution for 4(5x-2)/4-6(3x+2)/7=42-5(7x-4)/4 equation: 



4(5x-2)/4-6(3x+2)/7=42-5(7x-4)/4

We move all terms to the left:

4(5x-2)/4-6(3x+2)/7-(42-5(7x-4)/4)=0

We calculate fractions


(140x-56)/()+(-18x)/()+(-(42-5(7x-4)*7)/()=0



We calculate terms in parentheses: +(-(42-5(7x-4)*7)/(), so:

-(42-5(7x-4)*7)/(

We multiply all the terms by the denominator


-(42-5(7x-4)*7)



We calculate terms in parentheses: -(42-5(7x-4)*7), so:

42-5(7x-4)*7

determiningTheFunctionDomain
-5(7x-4)*7+42

We multiply parentheses

-245x+140+42

We add all the numbers together, and all the variables

-245x+182

Back to the equation:

-(-245x+182)



We get rid of parentheses

245x-182

Back to the equation:

+(245x-182)



We get rid of parentheses

(140x-56)/()+(-18x)/()+245x-182=0

We multiply all the terms by the denominator


(140x-56)+(-18x)+245x*()-182*()=0

We add all the numbers together, and all the variables

(140x-56)+(-18x)+245x*()=0

We get rid of parentheses

140x-18x+245x*()-56=0

We add all the numbers together, and all the variables

122x+245x*()-56=0

We move all terms containing x to the left, all other terms to the right

122x+245x*()=56

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