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4(5x-2)=2x(9x+3)
We move all terms to the left:
4(5x-2)-(2x(9x+3))=0
We multiply parentheses
20x-(2x(9x+3))-8=0
We calculate terms in parentheses: -(2x(9x+3)), so:We get rid of parentheses
2x(9x+3)
We multiply parentheses
18x^2+6x
Back to the equation:
-(18x^2+6x)
-18x^2+20x-6x-8=0
We add all the numbers together, and all the variables
-18x^2+14x-8=0
a = -18; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·(-18)·(-8)
Δ = -380
Delta is less than zero, so there is no solution for the equation
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