4(5x-20)=(9x+3)

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Solution for 4(5x-20)=(9x+3) equation: 



4(5x-20)=(9x+3)

We move all terms to the left:

4(5x-20)-((9x+3))=0

We multiply parentheses

20x-((9x+3))-80=0



We calculate terms in parentheses: -((9x+3)), so:

(9x+3)

We get rid of parentheses

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

20x-9x-3-80=0

We add all the numbers together, and all the variables

11x-83=0

We move all terms containing x to the left, all other terms to the right

11x=83

x=83/11

x=7+6/11

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