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4(5x-3)(3x+8)=0
We multiply parentheses ..
4(+15x^2+40x-9x-24)=0
We multiply parentheses
60x^2+160x-36x-96=0
We add all the numbers together, and all the variables
60x^2+124x-96=0
a = 60; b = 124; c = -96;
Δ = b2-4ac
Δ = 1242-4·60·(-96)
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38416}=196$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(124)-196}{2*60}=\frac{-320}{120} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(124)+196}{2*60}=\frac{72}{120} =3/5 $
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