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4(5x-3)-2(5x-11)=3(3x+2)-2
We move all terms to the left:
4(5x-3)-2(5x-11)-(3(3x+2)-2)=0
We multiply parentheses
20x-10x-(3(3x+2)-2)-12+22=0
We calculate terms in parentheses: -(3(3x+2)-2), so:We add all the numbers together, and all the variables
3(3x+2)-2
We multiply parentheses
9x+6-2
We add all the numbers together, and all the variables
9x+4
Back to the equation:
-(9x+4)
10x-(9x+4)+10=0
We get rid of parentheses
10x-9x-4+10=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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