4(5x-3)=6(-2x)+20

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Solution for 4(5x-3)=6(-2x)+20 equation: 



4(5x-3)=6(-2x)+20

We move all terms to the left:

4(5x-3)-(6(-2x)+20)=0

We multiply parentheses

20x-(6(-2x)+20)-12=0



We calculate terms in parentheses: -(6(-2x)+20), so:

6(-2x)+20

We multiply parentheses

-12x+20

Back to the equation:

-(-12x+20)



We get rid of parentheses

20x+12x-20-12=0

We add all the numbers together, and all the variables

32x-32=0

We move all terms containing x to the left, all other terms to the right

32x=32

x=32/32

x=1

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