4(5x-3)=7x+21

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Solution for 4(5x-3)=7x+21 equation: 



4(5x-3)=7x+21

We move all terms to the left:

4(5x-3)-(7x+21)=0

We multiply parentheses

20x-(7x+21)-12=0

We get rid of parentheses

20x-7x-21-12=0

We add all the numbers together, and all the variables

13x-33=0

We move all terms containing x to the left, all other terms to the right

13x=33

x=33/13

x=2+7/13

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