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4(5x-6)+5=4+3(2x+2)
We move all terms to the left:
4(5x-6)+5-(4+3(2x+2))=0
We multiply parentheses
20x-(4+3(2x+2))-24+5=0
We calculate terms in parentheses: -(4+3(2x+2)), so:We add all the numbers together, and all the variables
4+3(2x+2)
determiningTheFunctionDomain 3(2x+2)+4
We multiply parentheses
6x+6+4
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
20x-(6x+10)-19=0
We get rid of parentheses
20x-6x-10-19=0
We add all the numbers together, and all the variables
14x-29=0
We move all terms containing x to the left, all other terms to the right
14x=29
x=29/14
x=2+1/14
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