4(5x-6)-19=17(x-4)+31

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Solution for 4(5x-6)-19=17(x-4)+31 equation: 



4(5x-6)-19=17(x-4)+31

We move all terms to the left:

4(5x-6)-19-(17(x-4)+31)=0

We multiply parentheses

20x-(17(x-4)+31)-24-19=0



We calculate terms in parentheses: -(17(x-4)+31), so:

17(x-4)+31

We multiply parentheses

17x-68+31

We add all the numbers together, and all the variables

17x-37

Back to the equation:

-(17x-37)



We add all the numbers together, and all the variables

20x-(17x-37)-43=0

We get rid of parentheses

20x-17x+37-43=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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