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4(5x-9)=30-2(x+2)
We move all terms to the left:
4(5x-9)-(30-2(x+2))=0
We multiply parentheses
20x-(30-2(x+2))-36=0
We calculate terms in parentheses: -(30-2(x+2)), so:We get rid of parentheses
30-2(x+2)
determiningTheFunctionDomain -2(x+2)+30
We multiply parentheses
-2x-4+30
We add all the numbers together, and all the variables
-2x+26
Back to the equation:
-(-2x+26)
20x+2x-26-36=0
We add all the numbers together, and all the variables
22x-62=0
We move all terms containing x to the left, all other terms to the right
22x=62
x=62/22
x=2+9/11
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