4(5y+1)+13=6(2y-5)-21

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Solution for 4(5y+1)+13=6(2y-5)-21 equation: 



4(5y+1)+13=6(2y-5)-21

We move all terms to the left:

4(5y+1)+13-(6(2y-5)-21)=0

We multiply parentheses

20y-(6(2y-5)-21)+4+13=0



We calculate terms in parentheses: -(6(2y-5)-21), so:

6(2y-5)-21

We multiply parentheses

12y-30-21

We add all the numbers together, and all the variables

12y-51

Back to the equation:

-(12y-51)



We add all the numbers together, and all the variables

20y-(12y-51)+17=0

We get rid of parentheses

20y-12y+51+17=0

We add all the numbers together, and all the variables

8y+68=0

We move all terms containing y to the left, all other terms to the right

8y=-68

y=-68/8

y=-8+1/2

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