4(5y+3)-(3y+1)=27

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Solution for 4(5y+3)-(3y+1)=27 equation: 



4(5y+3)-(3y+1)=27

We move all terms to the left:

4(5y+3)-(3y+1)-(27)=0

We multiply parentheses

20y-(3y+1)+12-27=0

We get rid of parentheses

20y-3y-1+12-27=0

We add all the numbers together, and all the variables

17y-16=0

We move all terms containing y to the left, all other terms to the right

17y=16

y=16/17

y=16/17

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