4(5y+3)=2(7y+6)

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Solution for 4(5y+3)=2(7y+6) equation:



4(5y+3)=2(7y+6)
We move all terms to the left:
4(5y+3)-(2(7y+6))=0
We multiply parentheses
20y-(2(7y+6))+12=0
We calculate terms in parentheses: -(2(7y+6)), so:
2(7y+6)
We multiply parentheses
14y+12
Back to the equation:
-(14y+12)
We get rid of parentheses
20y-14y-12+12=0
We add all the numbers together, and all the variables
6y=0
y=0/6
y=0

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