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4(5y-2)+1=5(y-5/3)-2
We move all terms to the left:
4(5y-2)+1-(5(y-5/3)-2)=0
We add all the numbers together, and all the variables
4(5y-2)-(5(+y-5/3)-2)+1=0
We multiply parentheses
20y-(5(+y-5/3)-2)-8+1=0
We multiply all the terms by the denominator
20y*3)-2)-(5(+y-5-8*3)-2)+1*3)-2)=0
We add all the numbers together, and all the variables
20y*3)-2)-(5(y-29)-2)+1*3)-2)=0
We add all the numbers together, and all the variables
20y*3)-2)-(5(y=0
Wy multiply elements
60y^2=0
a = 60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·60·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{120}=0$
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