4(5y-2)+3(2y+6)=25(3y+3)-19y

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Solution for 4(5y-2)+3(2y+6)=25(3y+3)-19y equation: 



4(5y-2)+3(2y+6)=25(3y+3)-19y

We move all terms to the left:

4(5y-2)+3(2y+6)-(25(3y+3)-19y)=0

We multiply parentheses

20y+6y-(25(3y+3)-19y)-8+18=0



We calculate terms in parentheses: -(25(3y+3)-19y), so:

25(3y+3)-19y

We add all the numbers together, and all the variables

-19y+25(3y+3)

We multiply parentheses

-19y+75y+75

We add all the numbers together, and all the variables

56y+75

Back to the equation:

-(56y+75)



We add all the numbers together, and all the variables

26y-(56y+75)+10=0

We get rid of parentheses

26y-56y-75+10=0

We add all the numbers together, and all the variables

-30y-65=0

We move all terms containing y to the left, all other terms to the right

-30y=65

y=65/-30

y=-2+1/6

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