4(5y-5)-5=27

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Solution for 4(5y-5)-5=27 equation: 



4(5y-5)-5=27

We move all terms to the left:

4(5y-5)-5-(27)=0

We add all the numbers together, and all the variables

4(5y-5)-32=0

We multiply parentheses

20y-20-32=0

We add all the numbers together, and all the variables

20y-52=0

We move all terms containing y to the left, all other terms to the right

20y=52

y=52/20

y=2+3/5

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