4(5z-1)-2(z+1)=13(z+1)

Solution for 4(5z-1)-2(z+1)=13(z+1) equation:

Simplifying
4(5z + -1) + -2(z + 1) = 13(z + 1)

Reorder the terms:
4(-1 + 5z) + -2(z + 1) = 13(z + 1)
(-1 * 4 + 5z * 4) + -2(z + 1) = 13(z + 1)
(-4 + 20z) + -2(z + 1) = 13(z + 1)

Reorder the terms:
-4 + 20z + -2(1 + z) = 13(z + 1)
-4 + 20z + (1 * -2 + z * -2) = 13(z + 1)
-4 + 20z + (-2 + -2z) = 13(z + 1)

Reorder the terms:
-4 + -2 + 20z + -2z = 13(z + 1)

Combine like terms: -4 + -2 = -6
-6 + 20z + -2z = 13(z + 1)

Combine like terms: 20z + -2z = 18z
-6 + 18z = 13(z + 1)

Reorder the terms:
-6 + 18z = 13(1 + z)
-6 + 18z = (1 * 13 + z * 13)
-6 + 18z = (13 + 13z)

Solving
-6 + 18z = 13 + 13z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-13z' to each side of the equation.
-6 + 18z + -13z = 13 + 13z + -13z

Combine like terms: 18z + -13z = 5z
-6 + 5z = 13 + 13z + -13z

Combine like terms: 13z + -13z = 0
-6 + 5z = 13 + 0
-6 + 5z = 13

Add '6' to each side of the equation.
-6 + 6 + 5z = 13 + 6

Combine like terms: -6 + 6 = 0
0 + 5z = 13 + 6
5z = 13 + 6

Combine like terms: 13 + 6 = 19
5z = 19

Divide each side by '5'.
z = 3.8

Simplifying
z = 3.8