4(5z-1)-2(z+2)=7(z+1)

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Solution for 4(5z-1)-2(z+2)=7(z+1) equation: 



4(5z-1)-2(z+2)=7(z+1)

We move all terms to the left:

4(5z-1)-2(z+2)-(7(z+1))=0

We multiply parentheses

20z-2z-(7(z+1))-4-4=0



We calculate terms in parentheses: -(7(z+1)), so:

7(z+1)

We multiply parentheses

7z+7

Back to the equation:

-(7z+7)



We add all the numbers together, and all the variables

18z-(7z+7)-8=0

We get rid of parentheses

18z-7z-7-8=0

We add all the numbers together, and all the variables

11z-15=0

We move all terms containing z to the left, all other terms to the right

11z=15

z=15/11

z=1+4/11

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