4(5z-1)-5(z+2)=13(z+1)

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Solution for 4(5z-1)-5(z+2)=13(z+1) equation:


Simplifying
4(5z + -1) + -5(z + 2) = 13(z + 1)

Reorder the terms:
4(-1 + 5z) + -5(z + 2) = 13(z + 1)
(-1 * 4 + 5z * 4) + -5(z + 2) = 13(z + 1)
(-4 + 20z) + -5(z + 2) = 13(z + 1)

Reorder the terms:
-4 + 20z + -5(2 + z) = 13(z + 1)
-4 + 20z + (2 * -5 + z * -5) = 13(z + 1)
-4 + 20z + (-10 + -5z) = 13(z + 1)

Reorder the terms:
-4 + -10 + 20z + -5z = 13(z + 1)

Combine like terms: -4 + -10 = -14
-14 + 20z + -5z = 13(z + 1)

Combine like terms: 20z + -5z = 15z
-14 + 15z = 13(z + 1)

Reorder the terms:
-14 + 15z = 13(1 + z)
-14 + 15z = (1 * 13 + z * 13)
-14 + 15z = (13 + 13z)

Solving
-14 + 15z = 13 + 13z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-13z' to each side of the equation.
-14 + 15z + -13z = 13 + 13z + -13z

Combine like terms: 15z + -13z = 2z
-14 + 2z = 13 + 13z + -13z

Combine like terms: 13z + -13z = 0
-14 + 2z = 13 + 0
-14 + 2z = 13

Add '14' to each side of the equation.
-14 + 14 + 2z = 13 + 14

Combine like terms: -14 + 14 = 0
0 + 2z = 13 + 14
2z = 13 + 14

Combine like terms: 13 + 14 = 27
2z = 27

Divide each side by '2'.
z = 13.5

Simplifying
z = 13.5

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