4(5z-1)-5(z+2)=2(z+1)

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Solution for 4(5z-1)-5(z+2)=2(z+1) equation:


Simplifying
4(5z + -1) + -5(z + 2) = 2(z + 1)

Reorder the terms:
4(-1 + 5z) + -5(z + 2) = 2(z + 1)
(-1 * 4 + 5z * 4) + -5(z + 2) = 2(z + 1)
(-4 + 20z) + -5(z + 2) = 2(z + 1)

Reorder the terms:
-4 + 20z + -5(2 + z) = 2(z + 1)
-4 + 20z + (2 * -5 + z * -5) = 2(z + 1)
-4 + 20z + (-10 + -5z) = 2(z + 1)

Reorder the terms:
-4 + -10 + 20z + -5z = 2(z + 1)

Combine like terms: -4 + -10 = -14
-14 + 20z + -5z = 2(z + 1)

Combine like terms: 20z + -5z = 15z
-14 + 15z = 2(z + 1)

Reorder the terms:
-14 + 15z = 2(1 + z)
-14 + 15z = (1 * 2 + z * 2)
-14 + 15z = (2 + 2z)

Solving
-14 + 15z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-14 + 15z + -2z = 2 + 2z + -2z

Combine like terms: 15z + -2z = 13z
-14 + 13z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-14 + 13z = 2 + 0
-14 + 13z = 2

Add '14' to each side of the equation.
-14 + 14 + 13z = 2 + 14

Combine like terms: -14 + 14 = 0
0 + 13z = 2 + 14
13z = 2 + 14

Combine like terms: 2 + 14 = 16
13z = 16

Divide each side by '13'.
z = 1.230769231

Simplifying
z = 1.230769231

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