4(6+5k)=7(k-4)

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Solution for 4(6+5k)=7(k-4) equation:



4(6+5k)=7(k-4)
We move all terms to the left:
4(6+5k)-(7(k-4))=0
We add all the numbers together, and all the variables
4(5k+6)-(7(k-4))=0
We multiply parentheses
20k-(7(k-4))+24=0
We calculate terms in parentheses: -(7(k-4)), so:
7(k-4)
We multiply parentheses
7k-28
Back to the equation:
-(7k-28)
We get rid of parentheses
20k-7k+28+24=0
We add all the numbers together, and all the variables
13k+52=0
We move all terms containing k to the left, all other terms to the right
13k=-52
k=-52/13
k=-4

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