4(6+5k)=7(k-4)

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Solution for 4(6+5k)=7(k-4) equation: 



4(6+5k)=7(k-4)

We move all terms to the left:

4(6+5k)-(7(k-4))=0

We add all the numbers together, and all the variables

4(5k+6)-(7(k-4))=0

We multiply parentheses

20k-(7(k-4))+24=0



We calculate terms in parentheses: -(7(k-4)), so:

7(k-4)

We multiply parentheses

7k-28

Back to the equation:

-(7k-28)



We get rid of parentheses

20k-7k+28+24=0

We add all the numbers together, and all the variables

13k+52=0

We move all terms containing k to the left, all other terms to the right

13k=-52

k=-52/13

k=-4

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