4(6-2)+7z=0;-8

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Solution for 4(6-2)+7z=0;-8 equation: 



4(6-2)+7z=0-8

We move all terms to the left:

4(6-2)+7z-(0-8)=0

We add all the numbers together, and all the variables

7z+44-(-8)=0

We add all the numbers together, and all the variables

7z+52=0

We move all terms containing z to the left, all other terms to the right

7z=-52

z=-52/7

z=-7+3/7

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