4(6-x)+2(3-x)-5=9(5+2x)

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Solution for 4(6-x)+2(3-x)-5=9(5+2x) equation: 



4(6-x)+2(3-x)-5=9(5+2x)

We move all terms to the left:

4(6-x)+2(3-x)-5-(9(5+2x))=0

We add all the numbers together, and all the variables

4(-1x+6)+2(-1x+3)-(9(2x+5))-5=0

We multiply parentheses

-4x-2x-(9(2x+5))+24+6-5=0



We calculate terms in parentheses: -(9(2x+5)), so:

9(2x+5)

We multiply parentheses

18x+45

Back to the equation:

-(18x+45)



We add all the numbers together, and all the variables

-6x-(18x+45)+25=0

We get rid of parentheses

-6x-18x-45+25=0

We add all the numbers together, and all the variables

-24x-20=0

We move all terms containing x to the left, all other terms to the right

-24x=20

x=20/-24

x=-5/6

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