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4(6-x)-39=16x-5(3+4x)
We move all terms to the left:
4(6-x)-39-(16x-5(3+4x))=0
We add all the numbers together, and all the variables
4(-1x+6)-(16x-5(4x+3))-39=0
We multiply parentheses
-4x-(16x-5(4x+3))+24-39=0
We calculate terms in parentheses: -(16x-5(4x+3)), so:We add all the numbers together, and all the variables
16x-5(4x+3)
We multiply parentheses
16x-20x-15
We add all the numbers together, and all the variables
-4x-15
Back to the equation:
-(-4x-15)
-4x-(-4x-15)-15=0
We get rid of parentheses
-4x+4x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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