4(6-x)=128

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Solution for 4(6-x)=128 equation: 



4(6-x)=128

We move all terms to the left:

4(6-x)-(128)=0

We add all the numbers together, and all the variables

4(-1x+6)-128=0

We multiply parentheses

-4x+24-128=0

We add all the numbers together, and all the variables

-4x-104=0

We move all terms containing x to the left, all other terms to the right

-4x=104

x=104/-4

x=-26

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