4(6-y)+2=10

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Solution for 4(6-y)+2=10 equation: 



4(6-y)+2=10

We move all terms to the left:

4(6-y)+2-(10)=0

We add all the numbers together, and all the variables

4(-1y+6)+2-10=0

We add all the numbers together, and all the variables

4(-1y+6)-8=0

We multiply parentheses

-4y+24-8=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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