4(6-z)-39=26z-5(3+6z)

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Solution for 4(6-z)-39=26z-5(3+6z) equation: 



4(6-z)-39=26z-5(3+6z)

We move all terms to the left:

4(6-z)-39-(26z-5(3+6z))=0

We add all the numbers together, and all the variables

4(-1z+6)-(26z-5(6z+3))-39=0

We multiply parentheses

-4z-(26z-5(6z+3))+24-39=0



We calculate terms in parentheses: -(26z-5(6z+3)), so:

26z-5(6z+3)

We multiply parentheses

26z-30z-15

We add all the numbers together, and all the variables

-4z-15

Back to the equation:

-(-4z-15)



We add all the numbers together, and all the variables

-4z-(-4z-15)-15=0

We get rid of parentheses

-4z+4z+15-15=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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