4(6a-3)=6+(a-7)+2a

Solution for 4(6a-3)=6+(a-7)+2a equation:

4(6a-3)=6+(a-7)+2a

We move all terms to the left:

4(6a-3)-(6+(a-7)+2a)=0

We multiply parentheses

24a-(6+(a-7)+2a)-12=0


We calculate terms in parentheses: -(6+(a-7)+2a), so:

6+(a-7)+2a

determiningTheFunctionDomain
(a-7)+2a+6

We add all the numbers together, and all the variables

2a+(a-7)+6

We get rid of parentheses

2a+a-7+6

We add all the numbers together, and all the variables

3a-1

Back to the equation:

-(3a-1)


We get rid of parentheses

24a-3a+1-12=0

We add all the numbers together, and all the variables

21a-11=0

We move all terms containing a to the left, all other terms to the right

21a=11

a=11/21

a=11/21