4(6b-2)-b+44=16(b+11)

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Solution for 4(6b-2)-b+44=16(b+11) equation: 



4(6b-2)-b+44=16(b+11)

We move all terms to the left:

4(6b-2)-b+44-(16(b+11))=0

We add all the numbers together, and all the variables

-1b+4(6b-2)-(16(b+11))+44=0

We multiply parentheses

-1b+24b-(16(b+11))-8+44=0



We calculate terms in parentheses: -(16(b+11)), so:

16(b+11)

We multiply parentheses

16b+176

Back to the equation:

-(16b+176)



We add all the numbers together, and all the variables

23b-(16b+176)+36=0

We get rid of parentheses

23b-16b-176+36=0

We add all the numbers together, and all the variables

7b-140=0

We move all terms containing b to the left, all other terms to the right

7b=140

b=140/7

b=20

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