4(6j-15)=6(28-2j)

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Solution for 4(6j-15)=6(28-2j) equation: 



4(6j-15)=6(28-2j)

We move all terms to the left:

4(6j-15)-(6(28-2j))=0

We add all the numbers together, and all the variables

4(6j-15)-(6(-2j+28))=0

We multiply parentheses

24j-(6(-2j+28))-60=0



We calculate terms in parentheses: -(6(-2j+28)), so:

6(-2j+28)

We multiply parentheses

-12j+168

Back to the equation:

-(-12j+168)



We get rid of parentheses

24j+12j-168-60=0

We add all the numbers together, and all the variables

36j-228=0

We move all terms containing j to the left, all other terms to the right

36j=228

j=228/36

j=6+1/3

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