4(6j-15)=6(38-2j

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Solution for 4(6j-15)=6(38-2j equation: 



4(6j-15)=6(38-2j

We move all terms to the left:

4(6j-15)-(6(38-2j)=0

We add all the numbers together, and all the variables

4(6j-15)-(6(-2j+38)=0

We multiply parentheses

24j-(6(-2j+38)-60=0

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