4(6r+3)+2(r+2)=4(6r+3)+2(r+2)=

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Solution for 4(6r+3)+2(r+2)=4(6r+3)+2(r+2)= equation: 



4(6r+3)+2(r+2)=4(6r+3)+2(r+2)=

We move all terms to the left:

4(6r+3)+2(r+2)-(4(6r+3)+2(r+2))=0

We multiply parentheses

24r+2r-(4(6r+3)+2(r+2))+12+4=0



We calculate terms in parentheses: -(4(6r+3)+2(r+2)), so:

4(6r+3)+2(r+2)

We multiply parentheses

24r+2r+12+4

We add all the numbers together, and all the variables

26r+16

Back to the equation:

-(26r+16)



We add all the numbers together, and all the variables

26r-(26r+16)+16=0

We get rid of parentheses

26r-26r-16+16=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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