4(6r+3)+2(r+2)=r

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Solution for 4(6r+3)+2(r+2)=r equation: 



4(6r+3)+2(r+2)=r

We move all terms to the left:

4(6r+3)+2(r+2)-(r)=0

We add all the numbers together, and all the variables

-1r+4(6r+3)+2(r+2)=0

We multiply parentheses

-1r+24r+2r+12+4=0

We add all the numbers together, and all the variables

25r+16=0

We move all terms containing r to the left, all other terms to the right

25r=-16

r=-16/25

r=-16/25

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