4(6r+3)=2(r+2)=

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Solution for 4(6r+3)=2(r+2)= equation: 



4(6r+3)=2(r+2)=

We move all terms to the left:

4(6r+3)-(2(r+2))=0

We multiply parentheses

24r-(2(r+2))+12=0



We calculate terms in parentheses: -(2(r+2)), so:

2(r+2)

We multiply parentheses

2r+4

Back to the equation:

-(2r+4)



We get rid of parentheses

24r-2r-4+12=0

We add all the numbers together, and all the variables

22r+8=0

We move all terms containing r to the left, all other terms to the right

22r=-8

r=-8/22

r=-4/11

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