4(6t-12)=3(20t+18)+15t

Solution for 4(6t-12)=3(20t+18)+15t equation:

4(6t-12)=3(20t+18)+15t

We move all terms to the left:

4(6t-12)-(3(20t+18)+15t)=0

We multiply parentheses

24t-(3(20t+18)+15t)-48=0


We calculate terms in parentheses: -(3(20t+18)+15t), so:

3(20t+18)+15t

We add all the numbers together, and all the variables

15t+3(20t+18)

We multiply parentheses

15t+60t+54

We add all the numbers together, and all the variables

75t+54

Back to the equation:

-(75t+54)


We get rid of parentheses

24t-75t-54-48=0

We add all the numbers together, and all the variables

-51t-102=0

We move all terms containing t to the left, all other terms to the right

-51t=102

t=102/-51

t=-2