4(6x-)-(3x-5)=40

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Solution for 4(6x-)-(3x-5)=40 equation: 



4(6x-)-(3x-5)=40

We move all terms to the left:

4(6x-)-(3x-5)-(40)=0

We add all the numbers together, and all the variables

4(+6x)-(3x-5)-40=0

We multiply parentheses

24x-(3x-5)-40=0

We get rid of parentheses

24x-3x+5-40=0

We add all the numbers together, and all the variables

21x-35=0

We move all terms containing x to the left, all other terms to the right

21x=35

x=35/21

x=1+2/3

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