4(6x-1)-4(2x-19)=3(5x+4)-3

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Solution for 4(6x-1)-4(2x-19)=3(5x+4)-3 equation: 



4(6x-1)-4(2x-19)=3(5x+4)-3

We move all terms to the left:

4(6x-1)-4(2x-19)-(3(5x+4)-3)=0

We multiply parentheses

24x-8x-(3(5x+4)-3)-4+76=0



We calculate terms in parentheses: -(3(5x+4)-3), so:

3(5x+4)-3

We multiply parentheses

15x+12-3

We add all the numbers together, and all the variables

15x+9

Back to the equation:

-(15x+9)



We add all the numbers together, and all the variables

16x-(15x+9)+72=0

We get rid of parentheses

16x-15x-9+72=0

We add all the numbers together, and all the variables

x+63=0

We move all terms containing x to the left, all other terms to the right

x=-63

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