4(6x-1)-4(2x-19)=3(5x+4)-3

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Solution for 4(6x-1)-4(2x-19)=3(5x+4)-3 equation:



4(6x-1)-4(2x-19)=3(5x+4)-3
We move all terms to the left:
4(6x-1)-4(2x-19)-(3(5x+4)-3)=0
We multiply parentheses
24x-8x-(3(5x+4)-3)-4+76=0
We calculate terms in parentheses: -(3(5x+4)-3), so:
3(5x+4)-3
We multiply parentheses
15x+12-3
We add all the numbers together, and all the variables
15x+9
Back to the equation:
-(15x+9)
We add all the numbers together, and all the variables
16x-(15x+9)+72=0
We get rid of parentheses
16x-15x-9+72=0
We add all the numbers together, and all the variables
x+63=0
We move all terms containing x to the left, all other terms to the right
x=-63

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