4(6x-20)=8x+40

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Solution for 4(6x-20)=8x+40 equation: 



4(6x-20)=8x+40

We move all terms to the left:

4(6x-20)-(8x+40)=0

We multiply parentheses

24x-(8x+40)-80=0

We get rid of parentheses

24x-8x-40-80=0

We add all the numbers together, and all the variables

16x-120=0

We move all terms containing x to the left, all other terms to the right

16x=120

x=120/16

x=7+1/2

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