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4(6x-5)(5x+4)=0
We multiply parentheses ..
4(+30x^2+24x-25x-20)=0
We multiply parentheses
120x^2+96x-100x-80=0
We add all the numbers together, and all the variables
120x^2-4x-80=0
a = 120; b = -4; c = -80;
Δ = b2-4ac
Δ = -42-4·120·(-80)
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38416}=196$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-196}{2*120}=\frac{-192}{240} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+196}{2*120}=\frac{200}{240} =5/6 $
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