4(6y+3)-23=-16-(3y+1)

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Solution for 4(6y+3)-23=-16-(3y+1) equation: 



4(6y+3)-23=-16-(3y+1)

We move all terms to the left:

4(6y+3)-23-(-16-(3y+1))=0

We multiply parentheses

24y-(-16-(3y+1))+12-23=0



We calculate terms in parentheses: -(-16-(3y+1)), so:

-16-(3y+1)

determiningTheFunctionDomain
-(3y+1)-16

We get rid of parentheses

-3y-1-16

We add all the numbers together, and all the variables

-3y-17

Back to the equation:

-(-3y-17)



We add all the numbers together, and all the variables

24y-(-3y-17)-11=0

We get rid of parentheses

24y+3y+17-11=0

We add all the numbers together, and all the variables

27y+6=0

We move all terms containing y to the left, all other terms to the right

27y=-6

y=-6/27

y=-2/9

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