4(6y-10)=8y+40

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Solution for 4(6y-10)=8y+40 equation: 



4(6y-10)=8y+40

We move all terms to the left:

4(6y-10)-(8y+40)=0

We multiply parentheses

24y-(8y+40)-40=0

We get rid of parentheses

24y-8y-40-40=0

We add all the numbers together, and all the variables

16y-80=0

We move all terms containing y to the left, all other terms to the right

16y=80

y=80/16

y=5

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