4(6z+3)=6(2z+6)

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Solution for 4(6z+3)=6(2z+6) equation: 



4(6z+3)=6(2z+6)

We move all terms to the left:

4(6z+3)-(6(2z+6))=0

We multiply parentheses

24z-(6(2z+6))+12=0



We calculate terms in parentheses: -(6(2z+6)), so:

6(2z+6)

We multiply parentheses

12z+36

Back to the equation:

-(12z+36)



We get rid of parentheses

24z-12z-36+12=0

We add all the numbers together, and all the variables

12z-24=0

We move all terms containing z to the left, all other terms to the right

12z=24

z=24/12

z=2

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