4(6z-1)-2(z+4)=3(z+1)

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Solution for 4(6z-1)-2(z+4)=3(z+1) equation:


Simplifying
4(6z + -1) + -2(z + 4) = 3(z + 1)

Reorder the terms:
4(-1 + 6z) + -2(z + 4) = 3(z + 1)
(-1 * 4 + 6z * 4) + -2(z + 4) = 3(z + 1)
(-4 + 24z) + -2(z + 4) = 3(z + 1)

Reorder the terms:
-4 + 24z + -2(4 + z) = 3(z + 1)
-4 + 24z + (4 * -2 + z * -2) = 3(z + 1)
-4 + 24z + (-8 + -2z) = 3(z + 1)

Reorder the terms:
-4 + -8 + 24z + -2z = 3(z + 1)

Combine like terms: -4 + -8 = -12
-12 + 24z + -2z = 3(z + 1)

Combine like terms: 24z + -2z = 22z
-12 + 22z = 3(z + 1)

Reorder the terms:
-12 + 22z = 3(1 + z)
-12 + 22z = (1 * 3 + z * 3)
-12 + 22z = (3 + 3z)

Solving
-12 + 22z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-12 + 22z + -3z = 3 + 3z + -3z

Combine like terms: 22z + -3z = 19z
-12 + 19z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-12 + 19z = 3 + 0
-12 + 19z = 3

Add '12' to each side of the equation.
-12 + 12 + 19z = 3 + 12

Combine like terms: -12 + 12 = 0
0 + 19z = 3 + 12
19z = 3 + 12

Combine like terms: 3 + 12 = 15
19z = 15

Divide each side by '19'.
z = 0.7894736842

Simplifying
z = 0.7894736842

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