4(6z-1)-3(z+1)=16(z+1)

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Solution for 4(6z-1)-3(z+1)=16(z+1) equation:


Simplifying
4(6z + -1) + -3(z + 1) = 16(z + 1)

Reorder the terms:
4(-1 + 6z) + -3(z + 1) = 16(z + 1)
(-1 * 4 + 6z * 4) + -3(z + 1) = 16(z + 1)
(-4 + 24z) + -3(z + 1) = 16(z + 1)

Reorder the terms:
-4 + 24z + -3(1 + z) = 16(z + 1)
-4 + 24z + (1 * -3 + z * -3) = 16(z + 1)
-4 + 24z + (-3 + -3z) = 16(z + 1)

Reorder the terms:
-4 + -3 + 24z + -3z = 16(z + 1)

Combine like terms: -4 + -3 = -7
-7 + 24z + -3z = 16(z + 1)

Combine like terms: 24z + -3z = 21z
-7 + 21z = 16(z + 1)

Reorder the terms:
-7 + 21z = 16(1 + z)
-7 + 21z = (1 * 16 + z * 16)
-7 + 21z = (16 + 16z)

Solving
-7 + 21z = 16 + 16z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-16z' to each side of the equation.
-7 + 21z + -16z = 16 + 16z + -16z

Combine like terms: 21z + -16z = 5z
-7 + 5z = 16 + 16z + -16z

Combine like terms: 16z + -16z = 0
-7 + 5z = 16 + 0
-7 + 5z = 16

Add '7' to each side of the equation.
-7 + 7 + 5z = 16 + 7

Combine like terms: -7 + 7 = 0
0 + 5z = 16 + 7
5z = 16 + 7

Combine like terms: 16 + 7 = 23
5z = 23

Divide each side by '5'.
z = 4.6

Simplifying
z = 4.6

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